How do you calculate the power consumption of a motor?

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Calculate the power the motor consumes while in operation. The equation is W = AV(sqrt 3) where A is amperes, V is volts, and sqrt 3 is the square root of 33 (about 1.73). W is the power consumption in watts. For example, if the electric motor uses 50 amps at 240 volts, the wattage is 50 x 240 x 1.73, or 20,760 watts.

What is power consumption formula?

Electrical Formulas Used For Power Consumption Calculations

TO DETERMINE: SINGLE-PHASE DIRECT CURRENT
KVA I x E 1000 ——–
Kilowatts I x E x PF 1000 I x E 1000
Horsepower I x E x %EFF x PF 746 I x E x %EFF 746
Amperes (when HP is known) HP x 746 E x %EFF x PF HP x 746 E x %EFF

How much power does a 1 hp motor consume?

So, 1 HP for 24 hour = 746×24= 17904 Watt-hour which is equal to 17904/1000= 17.904 units. Hence, 17.904 units of Power will be consumed by the 1 HP motor when run continuously for 24 hours.

How do I calculate power consumption of single phase motor?

Single phase power equations:

1. Real Power. Wapplied = U I PF / 1000 (1) where. Wapplied = real power (kilowatts, kW) U = voltage (volts, V) I = current (amps, A) PF = power factor – 0.7 – 0.95.
2. Total Power. W = U I / 1000 (2)
3. Brake Horsepower. WBHP = U I PF μ / 746 (3) where. WBHP = brake horsepower (hp) μ = device efficiency.

What is the efficiency formula?

Efficiency is often measured as the ratio of useful output to total input, which can be expressed with the mathematical formula r=P/C, where P is the amount of useful output (“product”) produced per the amount C (“cost”) of resources consumed.

What is the 3 phase power formula?

3-Phase Calculations. For 3-phase systems, we use the following equation: kW = (V × I × PF × 1.732) ÷ 1,000.

How much power does a motor consume?

Calculate the power the motor consumes while in operation. The equation is W = AV(sqrt 3) where A is amperes, V is volts, and sqrt 3 is the square root of 33 (about 1.73). W is the power consumption in watts. For example, if the electric motor uses 50 amps at 240 volts, the wattage is 50 x 240 x 1.73, or 20,760 watts.

How much power does a 1.5 hp motor consume?

1.5 hp = 1 kw =0.3 kwh for 20 minutes per day. Thus the energy required per day is = 1.119/3 = 0.373 kWh.

How many kW is a 1.5 hp motor?

Three Phase Motors

MOTOR RATING HP
0.56 kW 3/4 2.8
0.75 kW 1 3.2
1.1 kW 1.5 4.5
1.5 kW 2 5.8

How many kW is an amp?

You can use this kilowatt to amperes converter. Below you will find 3 examples of a kW to Amps conversion for: 4 kW central air conditioner (220 V).

kW To Amps Calculator.

Power (kW) Voltage (220 V) Amperage (A)
1 kW to Amps: 220 V 4.55 Amps
2 kW to Amps: 220 V 9.09 Amps
4 kW to Amps: 220 V 18.18 Amps
6 kW to Amps: 220 V 27.27 Amps
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How do you calculate power consumption?

So if you want to calculate electrical energy consumed, just multiply wattage rating of your appliance with the time for which it is in operation. For example, if you have a 10 watt bulbs & it operates for 100 hours then electrical energy consumed is 10*100 = 1000 watt. hour i.e. 1 kWhr i.e. one unit of electricity.

What is the formula for kW?

We find the power in kilowatts P(kW) by dividing the power in watts P(W) by 1,000. Here’s the Formula for Converting Watts Into Kilowatts: P(kW) = P(W) / 1,000.

What is work formula?

Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton. … One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

What is efficiency with example?

Efficiency is defined as the ability to produce something with a minimum amount of effort. An example of efficiency is a reduction in the number of workers needed to make a car.

How do you calculate overall efficiency?

1. Basically the overall efficiency is based on the net output and input. Efficiency is the ratio of net work output to the input. The overall efficiency can be written as:
2. n = {(sum of inputs)—(sum of losses)}/(sum of inputs)
3. In case of thermodynamics, it is:
4. n = {(heat supplied)—(heat rejected)}/(heat supplied) 